Solved question paper for Chemistry Mar-2018 (PSEB Class 12th)

Solved Question Paper

Chemistry Mar-2018

PSEB • Class 12th • 1st • Mar-2018

Chemistry previous year question papers on BRpaper help students looking for PSEB 12th Class Question Papers to browse Chemistry papers for board exam practice and revision. This subject section is useful for finding PSEB 12th Chemistry old question papers, PYQ-style papers, and related exam-preparation material where available, so students can study the question format, recurring topics, and marks pattern used in the Punjab board exam. If you are preparing for the Punjab School Education Board Class 12 Chemistry paper, this page can help you compare past question styles with sample paper and model paper trends, and focus on important questions more confidently. BRpaper is not the official website of Punjab School Education Board or any institution, and it does not publish official notices or academic updates.

Solved Questions

Solved
  1. Out of 1M urea solution and 1M Kc/ solution, which one has higher freezing point ?

    Very Short Answer Mar-2018 • PSEB Class 12th

    1M urea has a higher freezing point.

  2. what are the units of Rate constant for First order reaction ?

    Very Short Answer Mar-2018 • PSEB Class 12th

    Rate = K[A]1

      = Kmol-1

    R =       =>    S-1

  3. What' is Tollen's reagent ? 

    Very Short Answer Mar-2018 • PSEB Class 12th

    Tollen’s reagent is a chemical reagent used to determine the presence of aldehyde, aromatic aldehyde and hydroxyl ketone functional group.

  4. How is benzamide converted into benzylamine ?

    Very Short Answer Mar-2018 • PSEB Class 12th

    C2H5CONH2 + Br2 + 4KOH  C6H5NH2 + K2CO3 + 2KBr + 2H2O

  5. Predict the products in the following reaction : 

    Very Short Answer Mar-2018 • PSEB Class 12th

  6. The chemical name of Vitamin E ...................

    Very Short Answer Mar-2018 • PSEB Class 12th

    Alpha – Tocophenol; D – alpha Tocophenol.

  7. The class of drugs used for the treatment of cut or wound is :

    (a) Tranquillizers (c) Antihistamins

    (b) Antiseptics (d) AntiPyretic

    Very Short Answer Mar-2018 • PSEB Class 12th

    Antiseptics.

  8. Soft soaps are potassium salts of higher fatty acids.True/False

    Short Answer Mar-2018 • PSEB Class 12th

    True

     

  9. In a metallic oxide, oxide ions are arranged in cubic close packing. One sixth of the tetrahedral voids are occupied by cations p and one third of octahedral voids are occupied by the cation Q. Deduce the formula of the compound.

    Short Answer Mar-2018 • PSEB Class 12th

    (one sixth of tetrahedral) P  Q   O1→ (octahedral voids).

    => PQO3

  10. For a reaction rate law expresslon is :  

    Rate = K [A]1/2 [B]2 

    Can the reaction be an elementary ? Explain.

    Short Answer Mar-2018 • PSEB Class 12th

    Number of an elementary process would have a rate law order equal to its molecularity and therefore must be integer values.

    Rate = K[A]1/2    [B]2

    Order =

    Order = 2.5

    The order can be a fractional value. Hence it’s not an elementary reaction.

  11. Explain Mond's process used for refining of nickel?

    Short Answer Mar-2018 • PSEB Class 12th

    In this process, nickel is heated in the presence of carbon monoxide to form nickel tetra carbonyl which is a volatile complex.

    Ni + 4CO Ni(CO)4.

    Ni(CO)4 Ni + CO.

    The obtained nickel tetra carbonyl is decomposed by subjecting it to higher temperature to obtain nickel.

  12. Why do transition metals have high enthalpies of atomization?

    Short Answer Mar-2018 • PSEB Class 12th

    Transition elements have high effective nuclear charge and number of valence electrons. Therefore, they form strong metallic bonds. As a result, the enthalpies of atomization of transition elements is high.

  13. [Fe(CN)6]-3 is low spin complex but [Fe(H2O)6]+3 is high spin complex Explain

    Short Answer Mar-2018 • PSEB Class 12th

    In the presence of CN – the 3d electrons pair up leaving only one unpaired electron. The hybridisation is d2SP3 forming an inner orbital complex in the presence of H2O. 3d electrons do not pair up. The hybridisation is SP3d2 forming an outer orbital complex containing five unpaired electrons.

    [Fe(CN)6]-3 has a low spin complex because it has the lowest number of unpaired electrons for an octahedral iron(iii) complex. [Fe(H2O)6]-3has a high spin because it has the number of electrons.

  14. Why does acetylation of -NH2 group of aniline reduce its activity ?

    Short Answer Mar-2018 • PSEB Class 12th

    Acetylation of aniline reduces its activation effect because it results in decrease of electron density on nitrogen. Due resonance, the electron pair of nitrogen atom gets delocalised towards the carbonyl group.

    ​​​​​​​

  15. what are Biodegradable polymers ? Give chemical equation for the preparation of any one biodegradable Polymer.

    Short Answer Mar-2018 • PSEB Class 12th

    Biodegradable polymers are polymers which are degraded by micro-organisms within a given period of time so that biodegradable polymers and the degraded product do not cause effects on the environment egDextron, Nylon2-nylon-6.

    These polymers are mainly used for medical purposes such as surgical materials, tissue in growth materials for controlled drug release etc. They are also used in agriculture film seed coating, fast food wrappers etc. poly-B hydroxybutyrate-CO-B-hydroxyvalerate (PHBV) is a biodegradable aliphatic polyester.

  16. Write two structural differences between DNA and RNA.

    Long Answer Mar-2018 • PSEB Class 12th

    DNA

    RNA

    The sugar moiety in DNA molecules is b-D-2 deoxyribose.

    The sugar moiety in RNA molecules is b-Ribose.

    DNA contains uracil.

    RNA contains thymine.

    Doesn’t contain thymine.

    Doesn’t contain uracil.

    The helical structure of DNA is a double strand.

    The helical structure of RNA is a single strand.

  17. (a) Analysis shows nickel oxide has the formula Ni0.98 O1.00 what fraction of Ni exists as Ni2+ and Ni3+ ions in given oxide ?

    (b) Explain metal deficiency defect due to catron vacancies.

    Long Answer Mar-2018 • PSEB Class 12th

    (a) Formula of Ni0.98  O1.00

    So, the ratio of Ni : O  => 98: 100, hence there are 100 atoms of oxygen and 98 atoms of nickel.

    Let number of atoms of Ni2+ = x

    Let number of atoms of Ni3+ = 98-x

    Charge of Ni = charge on O

    Hence oxygen has a charge of -2

    3(98-x) + 2x = 2(100)

    294 – 3x + 2x = 200

    +x = +94

    x = 94

    percentage of Ni2+ = (atoms of Ni+2/ total number of Ni) 100

    =>

    => 96%

    Percentage of Ni3+ = 100 – Ni+2

                                      = 100 – 96

                                      = 4%

  18. (a) When HgI2, is added to aqueous solution of KI, why there is an increase in osmotic pressure of solution?

    (b) Commercially available HCl contains 38% HCl by mass. calculate molality of the solution.

    Long Answer Mar-2018 • PSEB Class 12th

    (a) Freezing point of the solution with increase. Mercuric Iodide will react with potassium iodide to form dipotassium tetra iodo mercury. The reaction is given by:-

    2KI + HgI2 = K2[HgI4]. This associate will decrease the number of ions in the solution as a result of Van’t Hoff factor will decrease as n decrease from 4 to 3.

    Molarity = 12.61 Molar and 7.96ml of HCl (38%) needed for 1.0 litres of 0.10 Molar HCl.

    (b) HCl(38%) =

    =

    => moles of HCl in 38g =

    => volume of solution containing 1.06 mole of HCl =

    Molarity of HCl (38%) =

    = 12.62Molar HCl

  19. (a) Explain Normal or Standard hydrogen electrode.

    (b) How much amount of substance is deposited by passing one Faraday of electricity?

    Long Answer Mar-2018 • PSEB Class 12th

    (a) The standard hydrogen electrode is the standard measurement of electrode potential for the thermodynamic scale of redox potentials. The standard hydrogen electrode is called (SHE) or maybe known as normal hydrogen electrode (NHE)

                  2H+ + 2e-→ H2(g) at 250C

    (b) Faraday is a unit of charge not electricity. Passing one faraday charge can yield one mole a substance having a single charge on each molecule or atom.

  20. OR

    19. Calculate the cell potential (Ecell) of the following cell at 298K.
    Ag(s) l AgNO3 (0.01M) || AgNO3 (1.0M) | Ag (s)
     

    Long Answer Mar-2018 • PSEB Class 12th

    Ag(s) | AgNO3 (0.01M) || AgNO3 (1.0) Ag(s)

    0.80 -

    0.80 – 0.0591

    0.80 – 0.051 * 1

    = 0.7409V

  21. (a) Give two differences between macromolecular colloids and associated colloids.

    (b) Explain the term dialysis. How can it be increased?

    Long Answer Mar-2018 • PSEB Class 12th

    (a)

    Macromolecular

    Associate colloids

    Macromolecular colloids are by dispersing macromolecules having colloidal size in proper dispersion.

    Associated colloids are formed by aggregation of particles at higher concentration to colloidal range.

    Example protein, starch colloids.

    Example micelles.

     

    (b) The main purpose of dialysis is to help patients with impaired renal function. When the kidneys are damaged, they are no longer able to remove waste and excess fluid from the blood stream efficiently. Wastes such as nitrogen and creatinine build up in the blood stream.

  22. Give reason :

    (a) H3PO4 is triprotic acid but H3PO3 is diprotic acid. Why?

    (b) NCl3 and PCl3, are hydrolysed differently. Why?

    Long Answer Mar-2018 • PSEB Class 12th

    (a) H3PO3 is a triprotic acid because it has 2P―OH bonds and 1P―H bonds. H3PO4  contains 3P―OH bonds therefore H3PO4 is a triprotic acid.

     

    (b) In NCl3, nitrogen and chlorine have similar electro-negativities resulting in non-polar bonds. Nitrogen doesn’t have empty d-orbitals so hydrolysis takes place with donation of a lone pair of electrons by nitrogen to the hydrogen atom by water.

    NCl3  + H2O → NH3 + 3HOCl

    In PCl3, phosphorus is less electronegative than Cl. They form polar bonds, so the positive polar charge on phosphorus attacks the lone pair of electrons.

    PCl3 + 3H2O → H3PO3 + 3HCl

  23. (a) Why phenols are acidic in nature?

    (b) Explain the mechanism of the following reaction:-

    Long Answer Mar-2018 • PSEB Class 12th

    (a) Phenol is a very weak acid. The position of equilibrium lies to the left. Phenol can lose a hydrogen ion because the phenoxide ion formed is stabilised to some extent. The negative charge on the oxygen atom is delocalised around the ring. The more stable the ion.

    (b) Diagram to show mechanism of the reaction:-

    Step 1:-

    Step 2:-

  24. (a) What are Etard Reaction and Gattermann Koch Reaction ? Give one example of each.

    (b) Aldehydes are more reactive towards nucleophillic addition reactions than Ketones. Justify.

    Long Answer Mar-2018 • PSEB Class 12th

    (a) Etard reaction:-

    Etard reaction is used to produce benzaldehyde from toluene. Reagent used is CrO2Cl2.

    Toluene can be oxidised to benzaldehyde.

    Gattermann Koach reaction:-

     

    (b) This is because both show steric and electronic effect. In aldehydes, the relatively small hydrogen atom is attached to one side of the carbonyl group while a larger R group is affixed to the other side.

  25. OR

    23. (a) What are Claisen-Schmidt condensation and Kolbe's Reaction ? Give one example of each.

    (b) NH3 and its derivative do not show nucleophillic addition reactions with aldehydes and ketone in high acidic medium. Justify. 

    Long Answer Mar-2018 • PSEB Class 12th

    (a) Claisen Schmidt Condesation:-

    Eg. α –β unsaturated aldehyde.

    Kolbe’s Schmidt reaction:-

    Eg. in personal care product.

     

    (b) Many nucleophiles like ammonia and derivatives of ammonia can also be added to the carbonyl group of aldehydes and ketones. The reaction of ammonia and its derivatives is reversible and the reaction in the presence of an acid to form aaddtional products. The reaction equilibrium helps with production formation because fast dehydration of the intermediate complex.

    Hydrozones of aldehydes and ketones are not prepared in highly acidic medium. In highly acidic medium the protonation of hydrazine decreases in nucleophilic character. Hydrozones of aldehydes and ketones are not prepared in highly acidic medium.

  26. (a) Why CIF3 exists but FCl3 does not? 
          (b) Why ICl3 is more reactive than l2?  
          (c) Using VBT theory describe the shape of XeO4

    Long Answer Mar-2018 • PSEB Class 12th

    (a) Fluorine differs from the rest of other members because of its small size, high electro-negativity and non-availability of d-orbitals in the valence shell. Fluorine is the most reactive halogen due to its low enthalpy.

    (b) Sulphuric acid is an oily and viscous liquid because it is dense, colourless and a highly corrosive liquid most commonly known as hydrogen sulphate.

    (c) Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2

  27.  OR 

    24. (a) Why does Fluorine shows anomalous behavior ?  
    (b) Why sulphuric acid is oily and viscous liquid ?  
    (c) What happens when Cu reacts with cold dilute HNO3 ?

    Long Answer Mar-2018 • PSEB Class 12th

    (a) Fluorine does not possess d-orbitals, so it can’t expand its octet bond with three chlorine atoms and form FCl3. Chlorine on the other hand has empty d-orbitals and thus it can expand its octet to bond with three fluorine atoms to form ClF3.

    (b) ICl3 is more reactive than I2 because I―Cl bond in ICl is weaker than I―I bond in I2.

    (c) Xenon has 8 valence e-

    Oxygen has 6 valence e-

    xe = 4d10  5s2  5p6  5d8 (in ground state)

    In excited state:-

    These of e- form π bonds with the same oxygen atoms.

    Shape of XeO4 :-

    In fourth excited, xenon atom has 8 unpaired electrons. Shape of XeO4 is tetrahedral with a bond angle of 1090.

     

  28. (a) Why do Zr and Hf have similar properties ?

    (b) What happens when K2Cr2O7 is treated with H2SO4 and Nacl solution?

    (c)Transition metals form alloys easily?

    Long Answer Mar-2018 • PSEB Class 12th

    (a) Due to lanthanoide contraction.

    (b) 6NaCl      +     K2Cr2O7        +     H2SO4        →      3Cl2  +    Cr2(SO4)3    +         3Na2SO4      +      K2SO4     +     7H2O

    (sodium chloride)  (potassium dichromate)  (sulphuric acid)     (chlorine)     (chromium sulphate)   (sodium sulphate)  (potassium sulphate)  (water)  

    Sodium chloride reacts with potassium dichromate and sulphuric acid to produce chlorine, chromium sulphate, sodium sulphate, potassium sulphate and water.

    Sodium chloride should be solid and heated concentrated sulphuric acid solution.

    (c) The atomic radii of transition elements in any series are not much different from each other. They can very easily replace each other in the lattice and form solid solution, an appreciable composition range. Such solutions are called alloys.

  29. OR

    25. (a) What happens when K2Cr2O7 is heated strongly?  

    (b) Transition elements form complexes easily? Justify

    (c) Why 5d transition series elements have higher ionization enthalpies than 4d transition series elements? 

    Long Answer Mar-2018 • PSEB Class 12th

    (a) When heated strongly, it decomposes with evolution of oxygen.

    4K2Cr2O7→ 4K2CrO4 + 2Cr2O3 + 3O2

    (b) Transition elements are d-block elements. They have valence shell configuration of (n-1) d1-10. Because small size and higher nuclear charge, availability of valence d-orbital of suitable energy to accommodate lone pair of electrons donated by ligands.

    (c) 5-d elements have high nuclear charge than 4d- elements. Therefore, the outer electrons are attached strongly attached by nucleus in 5d – elements. On the other hand, shielding effect of 4f electron is very poor due to 5d elements.

  30. (a) Explain with example SN1 mechanism

    (b) Dipole moment of chlorobenzene is lower than that of cyclohexylcholoride. Give reason.

    Long Answer Mar-2018 • PSEB Class 12th

    (b) Chloro benzene is more electronegative than cyclohexyl chloride. The density of electrons in C―Cl bond of chlorine atom is less than that cyclohexyl chloride. This results into a decrease in the polarity of the C―Cl bond. Hence the dipole moment of chloro benzene is lower than cyclohexyl chloride.

  31. OR

    26. How will you convert the following ?

    (a) Ethyt bromide to Ethylisocyanide

    (b) Isopropylbromide to ProPene  

    (c) Anitine to Flourobenzene

    (d) Chlorobenzene to D.D.T.

    (e) Bromoethane to iodoethane.  

    (f) Chlorobenzene to Aniline.

    Long Answer Mar-2018 • PSEB Class 12th

    (a) Ethyl bromide + silver cyanide → ethyl isocyanide + silver bromide.

    CH₃CHâ‚‚-Br + AgCN → CH₃CHâ‚‚-NC + AgBr.

    (b) Isopropylbromide to Propene:-
     

    (c) Aniline to Flourobenzene:-

    (d) Chlorobenzene to D.D.T. :-

    (e) Bromoethane to iodoethane :-

    CH3CH2Cl + NaI   Acetone  CH3CH2I + Nacl

    (f) Chlorobenzene to Aniline:-

     

     

     

Explore all data

FAQ

Frequently Asked Questions

Answers about this subject, solved papers, and preparation.

Updated regularly
01 How can I find PSEB 12th Chemistry previous year question papers for 1st semester on BRpaper?

Open the Chemistry subject page under PSEB 12th Class Question Papers and use it to browse available Chemistry previous year papers for 1st semester revision and board-style practice.

02 Can this Chemistry page help me understand the PSEB Class 12 paper pattern?

Yes. Students often use previous Chemistry papers on this page to review question style, section flow, recurring topic areas, and the overall structure seen in past Punjab board exams.

03 Are previous year Chemistry papers useful along with sample paper or model paper practice?

Yes. Previous year papers show real past exam style, while sample or model papers are commonly used for extra pattern-based practice. Using both can help with revision and time-based preparation.

04 Can I use past Chemistry papers to identify important questions and repeated topics?

Past papers are often used to spot commonly tested areas in Chemistry, such as numericals and questions from organic, inorganic, or physical chemistry. They are helpful for setting revision priorities, not for guaranteeing exact repeats.

05 Does this page include solved Chemistry papers or answer keys?

This subject page is mainly for browsing previous year Chemistry question papers. If solution-based practice is available anywhere on the site, students should verify it on the page instead of assuming all papers include answers.

06 How should I prepare for the Chemistry exam in limited time using previous papers?

Start by reviewing a few past Chemistry papers to understand the question pattern, then revise the chapters that appear frequently, practice numericals, and use the papers for timed self-testing before the exam.