Solved question paper for Chemistry Mar-2018 (PSEB Class 12th)
Solved Question Paper
Chemistry Mar-2018
PSEB • Class 12th • 1st • Mar-2018
Chemistry previous year question papers on BRpaper help students looking for PSEB 12th Class Question Papers to browse Chemistry papers for board exam practice and revision. This subject section is useful for finding PSEB 12th Chemistry old question papers, PYQ-style papers, and related exam-preparation material where available, so students can study the question format, recurring topics, and marks pattern used in the Punjab board exam. If you are preparing for the Punjab School Education Board Class 12 Chemistry paper, this page can help you compare past question styles with sample paper and model paper trends, and focus on important questions more confidently. BRpaper is not the official website of Punjab School Education Board or any institution, and it does not publish official notices or academic updates.
Unit-I: Solid, State
Classification of solids based on different binding forces: molecular, ionic, covalent and metallic solids, amorphous and crystalline solids (elementary idea), unit cell in two dimensional and three dimensional lattices, calculation of density of unit cell, packing in solids packing efficiency, voids, number of atoms per unit cell in a cubic unit cell, points defects, electrical and magnetic properties. Band theory of metals, conductors, semiconductors and insulators and n and p type semiconductors.
Unit II: Solutions
Types of solutions, expression of concentration of solutions of solids in liquids, solubility of gases in liquids, solid solutions, colligative
properties - relative lowering of vapour pressure, Raoults Law, elevation of B.P., depression of freezing point, osmotic pressure, determination of molecular masses using colligative properties, abnormal molecular mass. Vant Hoff factor.
Unit III: Electrochemistry
Redox reactions; conductance in electrolytic solutions, specific and molar conductivity, variations of conductivity with concentration, Kohlrausch's Law, electrolysis and laws of electrolysis (elementary idea) dry cell-electrolytic cells and Galvanic cells; lead accumulator, EMF of a cell, standard electrode potential, Nernst equation and its application to chemical cells, fuel cells; corrosion. Relation between Gibbs Energy change and EMF of cell.
Unit IV: Chemical Kinetics
Rate of a reaction (average and instantaneous), factors affecting rates of reaction; concentration, temperature, catalyst; order and molecularity of a reaction: rate law and specific rate constant, integrated rate equations and' half life (only for zero and first order reactions); concept of collision theory (elementary idea, no mathematical treatment). Activation Energy, Arrhenious equation.
Unit V: Surface Chemistry
Absorption physiorption and chemisorption; factors affecting adsorption of gases on solids; catalysis; homogenous and heterogeneous,
activity and selectivity; enzyme catalysis; colloidal state: distinction between true solutions, colloids and suspensions; lyophillic, lyophobic, multimolecular and macromolecular/colloids; properties of colloids; Tyndall effect, Brownian movement, electrophoresis, coagulation; emulsion-types of emulsions.
Unit VI: General Principles and Processes of Isolation of Elements
Principles and methods of extraction – concentration, oxidation, reduction electrolytic method and refining; occurrence and principles of
extraction of aluminum, copper, zinc and Iron.
Unit VII: p-Block Element
Group 15 elements: General introduction, electronic configuration, occurrence, oxidation states, trends in physical and chemical
properties; nitrogen - preparation, properties and uses; compounds of nitrogen- preparation and properties of ammonia and nitric acids, oxides of nitrogen (structure only); Phosphorous-allotropic forms; compounds of phosphorous preparation and properties of phosphine, halides (PCl3,PCl5) and oxoacids (elementary idea only).
Group16 elements: General introduction, electronic configuration, oxidation states, occurrence, trends in physical and chemical
properties; dioxygen; preparation, properties and uses; classification of oxides; Ozone. Sulphur - allotropic forms; compounds of sulphur preparation, properties and uses of sulphur dioxide, sulphuric acid, industrial process of manufacture, properties and uses, oxoacids of sulphur (structures only).
Group 17 elements: (General introduction, electronic configuration, oxidation states, occurrence, trends in physical and chemical
properties; compounds of halogens; preparation, properties and uses of chlorine and hydrochloric acid, interhalogen compounds, oxoacids of halogens (structures only).
Group 18 elements: General introduction, electronic configuration. Occurrence, trends in physical and chemical properties, uses.
Unit-VIII: d and f Block Elements
General introduction, electronic configuration, occurrence and characteristics of transition metals, general trends in properties of the first
row transition metals-metallic character, ionization, enthalpy, oxidation states, ionic radii, colour, catalytic properties, magnetic properties, interstitial compounds, alloy formation. Preparation and properties of K2Cr2O7,and KMnO4. Lanthanoids - electronic configuration, oxidation states, chemical reactivity and lanthanoid contraction and consequences. Actenoids - Electronic configuration, oxidation states.
Unit-IX: Coordination Compounds
Coordination compounds - introduction, ligands, coordination number, colour, magnetic properties and shapes, IUPAC nomenclature of mononuclear coordination compounds, bonding; Werner’s theory VBT, CFT, Isomerism (structure and stereo) importance of coordination compounds (in qualitative analysis, extraction of metals and biological systems).
Unit-X: Haloalkanes and Haloarenes.
Haloalkanes: Nomenclature, nature of C-X bond, physical and chemical properties, mechanism of substitution reactions, optical rotation. Halearenes: Nature of C-X bond, substitution reactions (directive influence of halogen for monosubstituted compounds only) Uses and environmental effects of - dichloromethane, trichlromethane, tetrachloromethane, iodoform, freons, DDT.
Unit –XI: Alcohols, Phenols, and Ethers
Alcohols: Nomenclature, methods of preparation, physical and chemical properties (of primary alcohols only); identification of primary, secondary and tertiary alcohols; mechanism of dehydration, uses, with special reference to - methanol and ethanol. Phenols: Nomenclature, methods of preparation, physical and chemical properties, acidic nature of phenol, electrophilic substitution reactions, uses of phenols. Ethers: Nomenclature, methods of preparation, physical and chemical properties, uses.
Unit-XII: Aldehydes, Ketones aml Carboxylic Acids
Aldehydes and Ketones: Nomenclature, nature of carbonyl group, methods of preparation, physical and chemical properties, and mechanism of nucleophilic addition, reactivity of alpha hydrogen in aldehydes; uses. Carboxylic Acids: Nomenclature, acidic nature, methods of preparation, physical and chemical properties; uses.
Unit-XIII: Organic compounds containing Nitrogen
Amines: Nomenclature, classification, structure, methods of preparation, physical and chemical properties, uses, identification of primary,secondary and tertiary amines. Cyanides and Isocyanides - will be mentioned at relevant places in context. Dizonium Salts: Preparation, chemical reactions and importance in synthetic organic chemistry.
Unit-XIV: Biomolecules
Carbohydrates - Classification (aldoses and ketoses), monosaccaharides (glucose and fructose), oligosaccharides (sucrose, lactose, maltose), polysaccharides (starch, cellulose, glycogen); importance Proteins - Elementary idea of amino acids, peptide bond,polypeptides proteins, primary structure, secondary structure, tertiary structure and quaternary structure (qualitative idea only), denaturation of proteins; enzymes. Vitamins: Classification and functions. Harmones: Elementary idea (excluding structure) Nucleic Acids: DNA & RNA .
Unit-XV: Polymers
Classification - natural and synthetic, methods of polymerization (addition and condensation), copolymerization. Some important polymers; natural and synthetic like polythene, nylon, polyesters, bakelite, rubber. Biodegradable and Non- Biodegradable Polymers. Unit-XVI: Chemistry in everyday life :
1. Chemicals in medicines analgesic, transquilizers, antiseptics, disinfectants, antimicrobials, antifertility drugs, antibiotics, antacids,
antihistamines.
2. Chemicals in food- preservatives, artificial sweetening agents. Elementary idea of antioxidents.
3. Cleansing agents- soaps and detergents, cleansing action.
Solved Questions
Solved-
Out of 1M urea solution and 1M Kc/ solution, which one has higher freezing point ?
Very Short Answer Mar-2018 • PSEB Class 12th1M urea has a higher freezing point.
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Mar 2018
Out of 1M urea solution and IM KCl solution, which one has higher freezing point ?
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what are the units of Rate constant for First order reaction ?
Very Short Answer Mar-2018 • PSEB Class 12thRate = K[A]1
= Kmol-1
R =
=> S-1
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Mar 2018
What are the units of Rate constant for First Order reaction ?
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What' is Tollen's reagent ?
Very Short Answer Mar-2018 • PSEB Class 12thTollen’s reagent is a chemical reagent used to determine the presence of aldehyde, aromatic aldehyde and hydroxyl ketone functional group.
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Mar 2018
What is Tollen's reagent
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How is benzamide converted into benzylamine ?
Very Short Answer Mar-2018 • PSEB Class 12thC2H5CONH2 + Br2 + 4KOH →
C6H5NH2 + K2CO3 + 2KBr + 2H2O
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Mar 2018
How is benzamide converted into benzylamine?
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Predict the products in the following reaction :
Very Short Answer Mar-2018 • PSEB Class 12th
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Mar 2018
Predict the products in the following reaction :
\r\n\r\n
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The chemical name of Vitamin E ...................
Very Short Answer Mar-2018 • PSEB Class 12thAlpha – Tocophenol; D – alpha Tocophenol.
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Mar 2018
The chemical name of Vitamin E is ______________
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The class of drugs used for the treatment of cut or wound is :
(a) Tranquillizers (c) Antihistamins
(b) Antiseptics (d) AntiPyretic
Very Short Answer Mar-2018 • PSEB Class 12thAntiseptics.
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Mar 2018
The class of drugs used for the treatment of cut or wound is :
\r\n\r\n(a) Tranquillizers (b) Antiseptics (c) Antihistamins (d) Antipyretic
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Soft soaps are potassium salts of higher fatty acids.True/False
Short Answer Mar-2018 • PSEB Class 12thTrue
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Mar 2018
Soft soaps are potassium salts of higher fatty acids. True/False
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In a metallic oxide, oxide ions are arranged in cubic close packing. One sixth of the tetrahedral voids are occupied by cations p and one third of octahedral voids are occupied by the cation Q. Deduce the formula of the compound.
Short Answer Mar-2018 • PSEB Class 12th(one sixth of tetrahedral) P
Q
O1→ (octahedral voids).
=> PQO3
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Mar 2018
In a metallic oxide, oxide ions are arranged in cubic close packing. One sixth of the tetrahedral voids are occupied by cations P and one third of octahedral voids are occupied by the cation Q.
\r\n Deduce the formula of the compound.
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For a reaction rate law expresslon is :
Rate = K [A]1/2 [B]2
Can the reaction be an elementary ? Explain.
Short Answer Mar-2018 • PSEB Class 12thNumber of an elementary process would have a rate law order equal to its molecularity and therefore must be integer values.
Rate = K[A]1/2 [B]2
Order =
Order = 2.5
The order can be a fractional value. Hence it’s not an elementary reaction.
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Mar 2018
For a reaction rate law expression is :
\r\n
\r\nRate=K[A]1/2 [B]2
\r\n
\r\nCan the reaction be an elementary ? Explain.
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Explain Mond's process used for refining of nickel?
Short Answer Mar-2018 • PSEB Class 12thIn this process, nickel is heated in the presence of carbon monoxide to form nickel tetra carbonyl which is a volatile complex.
Ni + 4CO
Ni(CO)4.
Ni(CO)4
Ni + CO.
The obtained nickel tetra carbonyl is decomposed by subjecting it to higher temperature to obtain nickel.
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Mar 2018
Explain Mond's process used for refining of nickel.
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Why do transition metals have high enthalpies of atomization?
Short Answer Mar-2018 • PSEB Class 12thTransition elements have high effective nuclear charge and number of valence electrons. Therefore, they form strong metallic bonds. As a result, the enthalpies of atomization of transition elements is high.
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Mar 2018
Why do transition metals have high enthalpies of atomization ?
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[Fe(CN)6]-3 is low spin complex but [Fe(H2O)6]+3 is high spin complex Explain
Short Answer Mar-2018 • PSEB Class 12thIn the presence of CN – the 3d electrons pair up leaving only one unpaired electron. The hybridisation is d2SP3 forming an inner orbital complex in the presence of H2O. 3d electrons do not pair up. The hybridisation is SP3d2 forming an outer orbital complex containing five unpaired electrons.
[Fe(CN)6]-3 has a low spin complex because it has the lowest number of unpaired electrons for an octahedral iron(iii) complex. [Fe(H2O)6]-3has a high spin because it has the number of electrons.
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Mar 2018
[Fe(CN)6]-3 is low spin complex but [Fe(H2O)6]-3 is high spin complex. Explain.
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Why does acetylation of -NH2 group of aniline reduce its activity ?
Short Answer Mar-2018 • PSEB Class 12thAcetylation of aniline reduces its activation effect because it results in decrease of electron density on nitrogen. Due resonance, the electron pair of nitrogen atom gets delocalised towards the carbonyl group.
​​​​​​​-
Mar 2018
Why does acetylation of -NH, group of aniline reduce its activity ?
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what are Biodegradable polymers ? Give chemical equation for the preparation of any one biodegradable Polymer.
Short Answer Mar-2018 • PSEB Class 12thBiodegradable polymers are polymers which are degraded by micro-organisms within a given period of time so that biodegradable polymers and the degraded product do not cause effects on the environment egDextron, Nylon2-nylon-6.
These polymers are mainly used for medical purposes such as surgical materials, tissue in growth materials for controlled drug release etc. They are also used in agriculture film seed coating, fast food wrappers etc. poly-B hydroxybutyrate-CO-B-hydroxyvalerate (PHBV) is a biodegradable aliphatic polyester.

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Mar 2018
What are biodegradable polymers ? Give chemical equation for the preparation of any one biodegradable polymer.
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Write two structural differences between DNA and RNA.
Long Answer Mar-2018 • PSEB Class 12thDNA
RNA
The sugar moiety in DNA molecules is b-D-2 deoxyribose.
The sugar moiety in RNA molecules is b-Ribose.
DNA contains uracil.
RNA contains thymine.
Doesn’t contain thymine.
Doesn’t contain uracil.
The helical structure of DNA is a double strand.
The helical structure of RNA is a single strand.
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Mar 2018
Write two structural differences between DNA and RNA.
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(a) Analysis shows nickel oxide has the formula Ni0.98 O1.00 what fraction of Ni exists as Ni2+ and Ni3+ ions in given oxide ?
(b) Explain metal deficiency defect due to catron vacancies.
Long Answer Mar-2018 • PSEB Class 12th(a) Formula of Ni0.98 O1.00
So, the ratio of Ni : O => 98: 100, hence there are 100 atoms of oxygen and 98 atoms of nickel.
Let number of atoms of Ni2+ = x
Let number of atoms of Ni3+ = 98-x
Charge of Ni = charge on O
Hence oxygen has a charge of -2
3(98-x) + 2x = 2(100)
294 – 3x + 2x = 200
+x = +94
x = 94
percentage of Ni2+ = (atoms of Ni+2/ total number of Ni) 100
=>
=> 96%
Percentage of Ni3+ = 100 – Ni+2
= 100 – 96
= 4%
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Mar 2018
(a) Analysis shows nickel oxide has the formula Ni0.93 O1.00 What fraction of Ni exists as Ni3+ and Ni2+ ions in given oxide ?
\r\n
\r\n(b) Explain metal deficiency defect due to cation vacancies.
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(a) When HgI2, is added to aqueous solution of KI, why there is an increase in osmotic pressure of solution?
(b) Commercially available HCl contains 38% HCl by mass. calculate molality of the solution.
Long Answer Mar-2018 • PSEB Class 12th(a) Freezing point of the solution with increase. Mercuric Iodide will react with potassium iodide to form dipotassium tetra iodo mercury. The reaction is given by:-
2KI + HgI2 = K2[HgI4]. This associate will decrease the number of ions in the solution as a result of Van’t Hoff factor will decrease as n decrease from 4 to 3.
Molarity = 12.61 Molar and 7.96ml of HCl (38%) needed for 1.0 litres of 0.10 Molar HCl.
(b) HCl(38%) =
=
=> moles of HCl in 38g =
=> volume of solution containing 1.06 mole of HCl =
Molarity of HCl (38%) =
= 12.62Molar HCl
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Mar 2018
(a) When HgI2 is added to aqueous solution of KI, why there is an increase in osmotic pressure of solution ? Commercially available HCl contains 38% HCl by mass.
\r\n
\r\n
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(a) Explain Normal or Standard hydrogen electrode.
(b) How much amount of substance is deposited by passing one Faraday of electricity?
Long Answer Mar-2018 • PSEB Class 12th(a) The standard hydrogen electrode is the standard measurement of electrode potential for the thermodynamic scale of redox potentials. The standard hydrogen electrode is called (SHE) or maybe known as normal hydrogen electrode (NHE)
2H+ + 2e-→ H2(g) at 250C
(b) Faraday is a unit of charge not electricity. Passing one faraday charge can yield one mole a substance having a single charge on each molecule or atom.
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Mar 2018
(a) Explain Normal or Standard hydrogen electrode.
\r\n
\r\n(b) How much amount of substance is deposited by passing one Faraday of electricity ?
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OR
19. Calculate the cell potential (Ecell) of the following cell at 298K.
Ag(s) l AgNO3 (0.01M) || AgNO3 (1.0M) | Ag (s)
Long Answer Mar-2018 • PSEB Class 12thAg(s) | AgNO3 (0.01M) || AgNO3 (1.0) Ag(s)
0.80 -
0.80 – 0.0591
0.80 – 0.051 * 1
= 0.7409V
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Mar 2018
Or
Calculate the cell potential (EIN) of the following cell at 298K.
Ag(s) | AgNO3 (0.01M) || AgNO3 (1.OM) Ag(s
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(a) Give two differences between macromolecular colloids and associated colloids.
(b) Explain the term dialysis. How can it be increased?
Long Answer Mar-2018 • PSEB Class 12th(a)
Macromolecular
Associate colloids
Macromolecular colloids are by dispersing macromolecules having colloidal size in proper dispersion.
Associated colloids are formed by aggregation of particles at higher concentration to colloidal range.
Example protein, starch colloids.
Example micelles.
(b) The main purpose of dialysis is to help patients with impaired renal function. When the kidneys are damaged, they are no longer able to remove waste and excess fluid from the blood stream efficiently. Wastes such as nitrogen and creatinine build up in the blood stream.
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Mar 2018
(a) Give two differences between macromolecular colloids and associated colloids.
\r\n
\r\n(b) Explain the term dialysis. How can it be increased ?
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Give reason :
(a) H3PO4 is triprotic acid but H3PO3 is diprotic acid. Why?
(b) NCl3 and PCl3, are hydrolysed differently. Why?
Long Answer Mar-2018 • PSEB Class 12th(a) H3PO3 is a triprotic acid because it has 2P―OH bonds and 1P―H bonds. H3PO4 contains 3P―OH bonds therefore H3PO4 is a triprotic acid.

(b) In NCl3, nitrogen and chlorine have similar electro-negativities resulting in non-polar bonds. Nitrogen doesn’t have empty d-orbitals so hydrolysis takes place with donation of a lone pair of electrons by nitrogen to the hydrogen atom by water.
NCl3 + H2O → NH3 + 3HOCl
In PCl3, phosphorus is less electronegative than Cl. They form polar bonds, so the positive polar charge on phosphorus attacks the lone pair of electrons.
PCl3 + 3H2O → H3PO3 + 3HCl
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Mar 2018
Give reason :
\r\n
\r\n(a) H3PO4 is triprotic acid but H3PO3, is diprotic acid. Why?
\r\n
\r\n(b) NCI3 and PC3 are hydrolysed differently. Why?
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(a) Why phenols are acidic in nature?
(b) Explain the mechanism of the following reaction:-
Long Answer Mar-2018 • PSEB Class 12th(a) Phenol is a very weak acid. The position of equilibrium lies to the left. Phenol can lose a hydrogen ion because the phenoxide ion formed is stabilised to some extent. The negative charge on the oxygen atom is delocalised around the ring. The more stable the ion.

(b) Diagram to show mechanism of the reaction:-
Step 1:-

Step 2:-

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(a) What are Etard Reaction and Gattermann Koch Reaction ? Give one example of each.
(b) Aldehydes are more reactive towards nucleophillic addition reactions than Ketones. Justify.
Long Answer Mar-2018 • PSEB Class 12th(a) Etard reaction:-
Etard reaction is used to produce benzaldehyde from toluene. Reagent used is CrO2Cl2.Toluene can be oxidised to benzaldehyde.
Gattermann Koach reaction:-

(b) This is because both show steric and electronic effect. In aldehydes, the relatively small hydrogen atom is attached to one side of the carbonyl group while a larger R group is affixed to the other side.
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OR
23. (a) What are Claisen-Schmidt condensation and Kolbe's Reaction ? Give one example of each.
(b) NH3 and its derivative do not show nucleophillic addition reactions with aldehydes and ketone in high acidic medium. Justify.
Long Answer Mar-2018 • PSEB Class 12th(a) Claisen Schmidt Condesation:-

Eg. α –β unsaturated aldehyde.
Kolbe’s Schmidt reaction:-

Eg. in personal care product.
(b) Many nucleophiles like ammonia and derivatives of ammonia can also be added to the carbonyl group of aldehydes and ketones. The reaction of ammonia and its derivatives is reversible and the reaction in the presence of an acid to form aaddtional products. The reaction equilibrium helps with production formation because fast dehydration of the intermediate complex.

Hydrozones of aldehydes and ketones are not prepared in highly acidic medium. In highly acidic medium the protonation of hydrazine decreases in nucleophilic character. Hydrozones of aldehydes and ketones are not prepared in highly acidic medium.
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(a) Why CIF3 exists but FCl3 does not?
(b) Why ICl3 is more reactive than l2?
(c) Using VBT theory describe the shape of XeO4Long Answer Mar-2018 • PSEB Class 12th(a) Fluorine differs from the rest of other members because of its small size, high electro-negativity and non-availability of d-orbitals in the valence shell. Fluorine is the most reactive halogen due to its low enthalpy.
(b) Sulphuric acid is an oily and viscous liquid because it is dense, colourless and a highly corrosive liquid most commonly known as hydrogen sulphate.
(c) Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2
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Mar 2018
(a) Why CIF3 exists but FCl3 does not?
\r\n (b) Why ICl3 is more reactive than l2?
\r\n (c) Using VBT theory describe the shape of XeO4
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OR
24. (a) Why does Fluorine shows anomalous behavior ?
(b) Why sulphuric acid is oily and viscous liquid ?
(c) What happens when Cu reacts with cold dilute HNO3 ?Long Answer Mar-2018 • PSEB Class 12th(a) Fluorine does not possess d-orbitals, so it can’t expand its octet bond with three chlorine atoms and form FCl3. Chlorine on the other hand has empty d-orbitals and thus it can expand its octet to bond with three fluorine atoms to form ClF3.
(b) ICl3 is more reactive than I2 because I―Cl bond in ICl is weaker than I―I bond in I2.
(c) Xenon has 8 valence e-
Oxygen has 6 valence e-
xe = 4d10 5s2 5p6 5d8 (in ground state)
In excited state:-

These of e- form π bonds with the same oxygen atoms.
Shape of XeO4 :-

In fourth excited, xenon atom has 8 unpaired electrons. Shape of XeO4 is tetrahedral with a bond angle of 1090.
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Mar 2018
Or
(a) Why does Fluorine shows anomalous behavior ?
(b) Why sulphuric acid is oily and viscous liquid ?
(c) What happens when Cu reacts with cold dilute HNO3 ?
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(a) Why do Zr and Hf have similar properties ?
(b) What happens when K2Cr2O7 is treated with H2SO4 and Nacl solution?
(c)Transition metals form alloys easily?
Long Answer Mar-2018 • PSEB Class 12th(a) Due to lanthanoide contraction.
(b) 6NaCl + K2Cr2O7 + H2SO4 → 3Cl2 + Cr2(SO4)3 + 3Na2SO4 + K2SO4 + 7H2O
(sodium chloride) (potassium dichromate) (sulphuric acid) (chlorine) (chromium sulphate) (sodium sulphate) (potassium sulphate) (water)
Sodium chloride reacts with potassium dichromate and sulphuric acid to produce chlorine, chromium sulphate, sodium sulphate, potassium sulphate and water.
Sodium chloride should be solid and heated concentrated sulphuric acid solution.
(c) The atomic radii of transition elements in any series are not much different from each other. They can very easily replace each other in the lattice and form solid solution, an appreciable composition range. Such solutions are called alloys.
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OR
25. (a) What happens when K2Cr2O7 is heated strongly?
(b) Transition elements form complexes easily? Justify
(c) Why 5d transition series elements have higher ionization enthalpies than 4d transition series elements?
Long Answer Mar-2018 • PSEB Class 12th(a) When heated strongly, it decomposes with evolution of oxygen.
4K2Cr2O7→ 4K2CrO4 + 2Cr2O3 + 3O2
(b) Transition elements are d-block elements. They have valence shell configuration of (n-1) d1-10. Because small size and higher nuclear charge, availability of valence d-orbital of suitable energy to accommodate lone pair of electrons donated by ligands.
(c) 5-d elements have high nuclear charge than 4d- elements. Therefore, the outer electrons are attached strongly attached by nucleus in 5d – elements. On the other hand, shielding effect of 4f electron is very poor due to 5d elements.
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(a) Explain with example SN1 mechanism
(b) Dipole moment of chlorobenzene is lower than that of cyclohexylcholoride. Give reason.
Long Answer Mar-2018 • PSEB Class 12th(b) Chloro benzene is more electronegative than cyclohexyl chloride. The density of electrons in C―Cl bond of chlorine atom is less than that cyclohexyl chloride. This results into a decrease in the polarity of the C―Cl bond. Hence the dipole moment of chloro benzene is lower than cyclohexyl chloride.
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OR
26. How will you convert the following ?
(a) Ethyt bromide to Ethylisocyanide
(b) Isopropylbromide to ProPene
(c) Anitine to Flourobenzene
(d) Chlorobenzene to D.D.T.
(e) Bromoethane to iodoethane.
(f) Chlorobenzene to Aniline.
Long Answer Mar-2018 • PSEB Class 12th(a) Ethyl bromide + silver cyanide → ethyl isocyanide + silver bromide.
CH₃CHâ‚‚-Br + AgCN → CH₃CHâ‚‚-NC + AgBr.
(b) Isopropylbromide to Propene:-

(c) Aniline to Flourobenzene:-

(d) Chlorobenzene to D.D.T. :-

(e) Bromoethane to iodoethane :-
CH3CH2Cl + NaI Acetone
CH3CH2I + Nacl
(f) Chlorobenzene to Aniline:-
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Mar 2018
How will you convert the following ?
(a) Ethyl bromide to Ethylisocyanide
(b) Isopropylbromide to Propene
(c) Aniline to Flourobenzene
(d) Chlorobenzene to D.D.T.(e) Bromoethane to iodoethane.
(f) Chlorobenzene to Aniline.
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